9x^2-8=71x

Solution for 9x^2-8=71x equation:

9x^2-8=71x

We move all terms to the left:

9x^2-8-(71x)=0

a = 9; b = -71; c = -8;
Δ = b2-4ac
Δ = -712-4·9·(-8)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-73}{2*9}=\frac{-2}{18}
=-1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+73}{2*9}=\frac{144}{18}
=8
$